Here’s a quick tip to make your integrals super fast in python. Suppose you wanted to integrate a function in 3D. We can start by import nquad from scipy and defining our function.

from scipy.integrate import nquad
from math import sqrt, exp, sin, cos

def f(x, y, z):
return sin(cos(sqrt(exp(x)**2 + exp(y)**2 + exp(z)**2)))

nquad makes it super easy to integrate a function in any number of dimensions, lets see:

ranges=((1, 2), (1, 2), (1, 2))
nquad(f, ranges)
(-0.14048187566074577, 1.4506979457578973e-08)

Let’s check how long it took:

%timeit nquad(f, ranges)
19.5 ms ± 222 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

Pretty good, right? Well let’s see if we can do better (because maybe with a different function we’ll need to). Numba is a just-in-time compiler focused on numeric python. Let’s give it a try:

import numba

It works by adding a @jit decorator to our function. It infers the types of the arguments when it sees them and compiles the function into LLVM bytecode. The result can be significantly faster (I’ve seen easily two orders of magnitude).

@numba.jit
def f(x, y, z):
return sin(cos(sqrt(exp(x)**2 + exp(y)**2 + exp(z)**2)))

Let’s see if it’s still correct and how long it takes:

print(nquad(f, ranges))
%timeit nquad(f, ranges)
(-0.14048187566074577, 1.4506979457578973e-08)
10.9 ms ± 17.3 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)

Hey! Twice as fast with no work at all! Pretty nice if you ask me. But there is one more layer. The nquad function calls our compiled function from python, meaning that every time it calls the function we’re getting python function call overhead. Fortunately, scipy now has support for LowLevelCallable types. The specifics are in the documentation, but basically you can use a c function from scipy and the nquad routine will call it directly, without indirection to the python interpreter.

from scipy import LowLevelCallable

I never particularly cared for this, until I also saw that Numba now supports generating c functions directly from Python! Scipy needs a c-level function with the signature double(int, double*), so we have to tell numba this is what we want. This is very easy. Unfortunately, this also means we are a bit more restricted in what we can do here.

from numba import cfunc, types, carray

c_sig = types.double(types.intc, types.CPointer(types.double))
@cfunc(c_sig)
def f(n, data):
total = 0.0
for i in range(n):
total += exp(data[i])**2
return sin(cos(sqrt(total)))
new_f = LowLevelCallable(f.ctypes)
%timeit nquad(new_f, ranges)
(-0.14048187566074577, 1.4506979457578973e-08)
6.2 ms ± 14.7 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)